X and the City: Modeling Aspects of Urban Life

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X and the City: Modeling Aspects of Urban Life Page 11

by Adam, John A.


  In closing this section, let us revisit equation (12.5) for the capacity qmax. In terms of the original parameters (see equation (12.1))

  It is clear from this formula that the capacity can be raised by decreasing the reaction time (a), decreasing the headway distance (s0), or increasing the desired maximum deceleration (b−1) (not a good idea), or indeed, any combination of these changes. Conversely, the capacity will be lowered by changing them in the opposite directions.

  It is appropriate to mention an “equation” from the field of psychology in this context, namely “Response = Sensitivity × Stimulus.” The response is usually identified as the acceleration (or deceleration) of the following vehicle, and experimental studies have shown that there is a high correlation between a driver’s response and the relative speed of the vehicle ahead—the stimulus. With this in mind, note that differentiation of equation (12.1) with respect to t yields

  This is a type of stimulus-response equation, although the sensitivity term (a + 2bu)−1 decreases with increasing speed u, so it is not a particularly useful interpretation in this regard.

  X = un: AN IMPROVED REACTION-TIME MODEL

  There is another avenue worth pursuing in connection with the reaction time T. If we define sn = xn−1 − xn as the spacing ahead of the nth car (at location xn), rewrite equation (11.3) in terms of the discrete speed un = dxn/dt, and let t → t − T, this equation becomes (with cn = 0)

  This differential-difference can be solved exactly using more advanced techniques, but we will use an approximate method consistent with the level of this book. We can expand the right-hand side of this equation as a Taylor series about t; retaining up to the quadratic term in T we obtain the expression

  Now

  and so on. Placing all the terms involving un on the left-hand side, and all those in un−1 on the right, we have the following constant coefficient second-order nonhomogeneous ordinary differential equation (quite a mouthful):

  If we know the speed of vehicle (n − 1), this equation enables us in principle to find the speed of the following vehicle (n). From the elementary theory of differential equations we know that the general solution of this equation is the sum of the solution to the homogeneous equation (i.e., with zero right-hand side) and a particular solution to the complete equation (with the right-hand side being a known function of t). The former solution is the most important determinant of the instability of the traffic flow, so we seek solutions of equation (12.10) in the form un(t) = Uept, where U is a constant. There are two values of the constant p to be found by substitution. These values are roots of the quadratic equation

  The nature of p (and hence the solution) depends on the sign of the radicand; it will be real (and hence non-oscillatory), provided

  Otherwise the roots are complex conjugates, and the sign of the real part determines the solution behavior. If

  (i) 0 ≤ bT ≤ − 1; both roots are negative and the solution is exponentially decreasing (stable).

  (ii) − 1 < bT < 1; both roots are complex, and the solution is damped oscillatory (stable).

  (iii) bT = 1; both roots are pure imaginary, and the solution is oscillatory (neutrally stable).

  (iv) bT > 1; both roots are complex, and the solution is increasing and oscillatory (unstable).

  What does all this mean? Remember that the solution un(t) = Uept is the speed of the nth vehicle in the line of traffic. From cases (i)–(iv) we see that (locally at least) the speed can decrease, oscillate about a decreasing mean value, oscillate about a constant mean value, and oscillate about an increasing mean value. This last case is indicative of the potential for collisions somewhere down the traffic line. The model is a crude one, to be sure, but this latter behavior is also consistent with the solution for the nonhomogeneous equation, known as the “particular integral.” The choice of functional form sought depends on that of the presumed known quantity un−1(t), but for our purposes it is sufficient, in light of (i)–(iv) above to consider an oscillatory solution of the form . Substituting this in equation (12.10) results in the expression

  Note that

  and this ratio grows as n increases if the expression on the right exceeds unity. Note that this term can be written in simplified form in terms of real and imaginary parts as

  It is clear that we require bT > 1/2 for |un/un−1| > 1. This then supersedes the previous criterion for instability because it “kicks in” at a lower value of bT.

  For completeness in this section, the exact solution for this problem is stated below:

  (i) 0 ≤ bT ≤ e−1 ≈ 0.368; both roots are negative and the solution is exponentially decreasing (stable).

  (ii) e−1 < bT < π/2 ≈ 1.571; both roots are complex, and the solution is damped oscillatory (stable).

  (iii) bT = π/2; both roots are pure imaginary, and the solution is oscillatory (neutrally stable).

  (iii) bT > π/2; both roots are complex, and the solution is increasing and oscillatory (unstable).

  The rough and ready calculations therefore have the right “character traits” insofar as stability and instability are concerned, but the transition points are inaccurate. However, it must be said that compared with the exact solution, the upper bound in part (i) above is an overestimate of only 11%, while the transition value in part (iii) is an underestimate of about 36%.

  Exercise: Show that, had we expanded equation (12.9) as a linear Taylor polynomial in T only, the results would have been very similar:

  (i) 0 ≤ 1 bT ≤ 1; root is negative and the solution is exponentially decreasing (stable).

  (ii) bT > 1; root is positive, and the solution is exponentially increasing (unstable)

  for the homogeneous solution and

  (iii) bT > 1/2 for the particular integral.

  Chapter 13

  CONGESTION IN THE CITY

  If all the cars in the United States were placed end to end, it would probably be Labor Day Weekend.

  —Doug Larson

  X = v(N): SOME EMPIRICAL MEASURES OF URBAN CONGESTION

  What percentage of our (waking) time do we spend driving? In the United States, a typical drive to and from work may be at least half an hour each way, frequently more in high density metropolitan areas. So for an 8-hr working day, the drive adds at least 12–13% to that time, during much of which drivers may become extremely frustrated. (Confession: I am not one of those people; I am fortunate enough to walk to work!)

  On 25 January 2011 my local newspaper carried an article entitled “Slow Motion.” The article took data from the American Community Survey (conducted by the U.S. Census Bureau) and presented average commuter travel times for the region. According to the survey, the NYC metro area had the highest “average commute time,” more than 38 minutes; Washington, DC, was second with 37 minutes, and Chicago was third with more than 34 minutes. (The piece in the newspaper stated the commute times to the nearest hundredth of a minute—about half a second—which is clearly silly!) The average for my locality was about 26 minutes.

  In much of what follows, the equations describing various features of traffic-related phenomena are based on detailed observational studies published in the literature. Consequently, the coefficients in many of these equations are not particularly “nice,” that is, not integers! For example, one measure of the capacity of a road network in a UK city center (London) was given by [25]

  where v1 is the average speed of traffic in mph (numerically). The traffic flow is more easily appreciated by inverting this to give the approximate expression v1 = (523 − 7.7N)1/2. For comparison, another empirical measure is also illustrated:

  As can be seen from Figure 13.1, the two formulae give similar results for speeds above about 12 mph, but in fact v1(N) (solid curve) is a better fit to the low-speed data. It should be emphasized that both N and v1,2 are numerical values associated with the units in which they are expressed, so equation (13.1) and others like it are dimensionless.

  Figure 13.1. v1 and v2 in mph vs. N (cars/hr/highway width
in ft)

  Of course, not all vehicles will be cars. In some of the literature [20]–[27], bicycles were regarded as the equivalent of one third of a car, buses the equivalent of three cars, and so forth. Thus, in order to achieve a speed of v mph, equation (13.1) suggests that each car on the road, during a period of one hour, requires a width of (68 − 0.13v2)−1 ft. A bus would require three times this width and a bicycle one third (a motorcycle, presumably, one half).

  GENERAL ALGEBRAIC EXPRESSIONS FOR TRAFFIC DYNAMICS

  X = δT: Question: How are increases in traffic and losses in time (due to congestion) related?

  As above, we’ll write N(v) as a quadratic function,

  where N0 = a and = a/b. N0 is interpreted as the maximum flow of vehicles and v0 as the speed under “light” traffic conditions. Suppose that a journey is of distance l and we define T, the accumulated time loss due to congestion, as the difference (for N vehicles) between the times traveled at speeds v and v0, respectively, then

  We shall define the relationship between small changes in T and N (δT and δN respectively) by

  where T′(N) is the derivative of T with respect to N. If T′ is not too large, a small change in N induces a correspondingly small change in T according to this formula. This is a slight variation on the definition of differentials in elementary calculus, but it will be quite sufficient an approximation for our purposes, and indeed a good one, so we will use “=” rather than “≈” in what follows. From equations (13.2) and (13.3) we obtain

  or

  As a function of the ratio v0/v, the right-hand side of (13.5) is a cubic polynomial, increasing monotonically from zero when the traffic is light (v0/v = 1). Graphically, it is perhaps easier to appreciate as a function of the ratio of speed to the “light” speed (not the speed of light!), that is, in terms of x = v/v0. Thus

  The graph of this decreases monotonically to zero when x = 1, and as can be seen in Figure 13.2, the congestion term on the left of equation (13.6) decreases by a factor of about twelve as x increases from 0.2 to 0.5; that is, when the average speed is one fifth of the speed of light traffic, the time loss is about twelve times as great as when the average speed is one half that of light traffic. Furthermore, from equations (13.2), (13.3), and (13.5) we can deduce an expression for the following useful measure of congestion:

  Figure 13.2. Graph of the function f(x) defined by equation (13.6).

  Clearly δT/T increases as a quadratic function of the percentage increase of traffic.

  X = δt: Question: What difference will just one more vehicle make?

  The change in time for a journey of length l and duration t = l/v when there is a small change δv in speed is given by δt = −lδv/v2. If this change arises because of a small change δN in the traffic flow, we may write

  Therefore, if N is the flow before I try to sneak my car into the traffic, the total increase in journey time of the other vehicles is approximately Nδt/δN, that is, −Nlv′(N)/v2. I do feel a little guilty about this, but I have to get to the bank before it closes. Using equation (13.2) this can be rewritten as

  We can extract more from this equation. The journey takes a time l/v, so that

  As may be seen from equation (13.9), this represents a significant time loss if the speed of traffic is low. And here is another point to note: equation (13.8) represents the time loss imposed on other vehicles by my entry into the traffic stream. If we add to this the time loss sustained by my vehicle, then the resulting sum must be the same as that expressed by equation (13.5), that is,

  Exercise: Verify this identity.

  X = dx/dt: Question: How fast do traffic back-ups increase in length?

  As we all know from experience, delays while driving can arise for several reasons: accidents or other obstructions, tunnels, bottlenecks at an intersection, raised bridges, or even a poorly adjusted traffic light at a busy junction. If the traffic flow is N vehicles at speed v, and joins a line of traffic (a traffic queue if you are reading this in the UK) with average flow N0 at speed v0, no line forms if N < N0. By contrast, if N > N0, a steadily increasing line forms (we are here excluding temporary back-ups that oscillate in length). In the latter case, the rate at which the line lengthens can be computed as follows. We denote the length of the back-up be x at time t, where x(0) = 0, that is, we suppose that the problem starts at time “zero.” Noting that the ratio N/v has units of (vehicles/hr) ÷ (mph), or vehicles/mile, it follows that at t = 0, a portion of road of length x contains Nx/v vehicles. At a later time t it contains N0x/v0, because of the back-up. Therefore the number of vehicles entering the stretch minus the number leaving it is (N − N0)t, but this is just the quantity . Hence the rate at which the back-up increases is

  In the question below we apply this formula to an all-too-common situation in many parts of the world.

  Question: Suppose the traffic is stationary. How fast is the line of traffic increasing?

  This means that N0 = 0 and v0 = 0; clearly this means that equation (13.11) is indeterminate, so how are we to interpret the ratio N0/v0 in this case? Dimensionally, N/v is the ratio of vehicles per unit time to speed, that is, vehicles/length, or vehicular density on the road. In the case of stationary traffic, as here, this is just the concentration of vehicles in the queue. We shall take the effective length of an “average” vehicle to include the space between each one and the vehicle ahead. As before, we’ll call this density k, so equation (13.11) reduces to

  This is the rate at which the traffic “jam” lengthens. Suppose, as an example, that we take the effective length for American vehicles (including the gap ahead) to be about 25 ft (it is probably less in Europe since the cars are typically smaller), and that the vehicles arrive at 30 mph, with a flow rate of, say, 500 vehicles per hour. The concentration per mile of the stationary line of cars, k, is then 5280 ÷ 25 ≈ 210 per mile. From (13.12) the line increases at a rate

  Obviously, one can plug in one’s own estimates based on different traffic conditions.

  Chapter 14

  ROADS IN THE CITY

  X = : Question: What is the average distance traveled in a city/town center?

  This can be quite a complicated quantity to calculate, depending as it does on the type of road network and distribution of starting points and destinations, among other factors. Smeed (1968) assumed a uniform distribution of origins and destinations for both idealized and real UK road networks, and with some simplifying assumptions, concluded that the range of values lay between 0.70A1/2 and 1.07A1/2, with a mean of 0.87A1/2, A being the area of the town center (assuming this can be suitably defined). Obviously the factor A1/2 renders the result dimensionally correct. With this behind us, the next stage is to try to determine the average length of a journey during say, a peak travel period. Using rather sophisticated statistical tools, Smeed was able to calculate the above average distance traveled on roads of any given town or city center, assuming only that the journeys are made by the shortest possible route. Rather than try to reproduce the (unpublished) calculations here, let us try to make these figures plausible on the basis of some simple geometric models of cities.

  We will just calculate the mean lengths of parallel roads in circular and rectangular town centers as we move from one side of the town center to the other. Even this rather crude approach yields answers close to those found in the literature, indicating that the coefficient is relatively insensitive to the structure of the road network. First, we consider a set of N-S parallel roads in a circular town center of radius r (see Figure 14.1), separated by a constant distance r/n, where n is a positive integer. In so doing, we are neglecting the combined width of the road network compared with the town center area. Each road passing within a distance pr/n of the origin (where p is an integer less than n) has length 2r[1 − (p/n)2]1/2, and for each p > 0 there are two roads of identical length. There are 2(n − 1) + 1 = 2n − 1 roads, so the discrete average length is given by

  Of course, an identical result holds for W-E roads, and the
combined average will be the same. To express in terms of A1/2 we merely write = kA1/2 = kπ1/2r, so that the coefficient . For n = 3 (five roads), k ≈ 0.99; for n = 4 (seven roads), k ≈ 0.96, and for n = 10 (nineteen roads), k ≈ 0.92. Thus we see that these constants are well within the range found by Smeed.

 

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